Optimal. Leaf size=211 \[ \frac{(13 A+83 i B) \sqrt{a+i a \tan (c+d x)}}{30 a^3 d}+\frac{41 A+151 i B}{60 a^2 d \sqrt{a+i a \tan (c+d x)}}+\frac{(A-i B) \tanh ^{-1}\left (\frac{\sqrt{a+i a \tan (c+d x)}}{\sqrt{2} \sqrt{a}}\right )}{4 \sqrt{2} a^{5/2} d}+\frac{(-B+i A) \tan ^3(c+d x)}{5 d (a+i a \tan (c+d x))^{5/2}}+\frac{(7 A+17 i B) \tan ^2(c+d x)}{30 a d (a+i a \tan (c+d x))^{3/2}} \]
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Rubi [A] time = 0.568629, antiderivative size = 211, normalized size of antiderivative = 1., number of steps used = 6, number of rules used = 5, integrand size = 36, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.139, Rules used = {3595, 3592, 3526, 3480, 206} \[ \frac{(13 A+83 i B) \sqrt{a+i a \tan (c+d x)}}{30 a^3 d}+\frac{41 A+151 i B}{60 a^2 d \sqrt{a+i a \tan (c+d x)}}+\frac{(A-i B) \tanh ^{-1}\left (\frac{\sqrt{a+i a \tan (c+d x)}}{\sqrt{2} \sqrt{a}}\right )}{4 \sqrt{2} a^{5/2} d}+\frac{(-B+i A) \tan ^3(c+d x)}{5 d (a+i a \tan (c+d x))^{5/2}}+\frac{(7 A+17 i B) \tan ^2(c+d x)}{30 a d (a+i a \tan (c+d x))^{3/2}} \]
Antiderivative was successfully verified.
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Rule 3595
Rule 3592
Rule 3526
Rule 3480
Rule 206
Rubi steps
\begin{align*} \int \frac{\tan ^3(c+d x) (A+B \tan (c+d x))}{(a+i a \tan (c+d x))^{5/2}} \, dx &=\frac{(i A-B) \tan ^3(c+d x)}{5 d (a+i a \tan (c+d x))^{5/2}}-\frac{\int \frac{\tan ^2(c+d x) \left (3 a (i A-B)+\frac{1}{2} a (A+11 i B) \tan (c+d x)\right )}{(a+i a \tan (c+d x))^{3/2}} \, dx}{5 a^2}\\ &=\frac{(i A-B) \tan ^3(c+d x)}{5 d (a+i a \tan (c+d x))^{5/2}}+\frac{(7 A+17 i B) \tan ^2(c+d x)}{30 a d (a+i a \tan (c+d x))^{3/2}}+\frac{\int \frac{\tan (c+d x) \left (-a^2 (7 A+17 i B)+\frac{1}{4} a^2 (13 i A-83 B) \tan (c+d x)\right )}{\sqrt{a+i a \tan (c+d x)}} \, dx}{15 a^4}\\ &=\frac{(i A-B) \tan ^3(c+d x)}{5 d (a+i a \tan (c+d x))^{5/2}}+\frac{(7 A+17 i B) \tan ^2(c+d x)}{30 a d (a+i a \tan (c+d x))^{3/2}}+\frac{(13 A+83 i B) \sqrt{a+i a \tan (c+d x)}}{30 a^3 d}+\frac{\int \frac{-\frac{1}{4} a^2 (13 i A-83 B)-a^2 (7 A+17 i B) \tan (c+d x)}{\sqrt{a+i a \tan (c+d x)}} \, dx}{15 a^4}\\ &=\frac{(i A-B) \tan ^3(c+d x)}{5 d (a+i a \tan (c+d x))^{5/2}}+\frac{(7 A+17 i B) \tan ^2(c+d x)}{30 a d (a+i a \tan (c+d x))^{3/2}}+\frac{41 A+151 i B}{60 a^2 d \sqrt{a+i a \tan (c+d x)}}+\frac{(13 A+83 i B) \sqrt{a+i a \tan (c+d x)}}{30 a^3 d}+\frac{(i A+B) \int \sqrt{a+i a \tan (c+d x)} \, dx}{8 a^3}\\ &=\frac{(i A-B) \tan ^3(c+d x)}{5 d (a+i a \tan (c+d x))^{5/2}}+\frac{(7 A+17 i B) \tan ^2(c+d x)}{30 a d (a+i a \tan (c+d x))^{3/2}}+\frac{41 A+151 i B}{60 a^2 d \sqrt{a+i a \tan (c+d x)}}+\frac{(13 A+83 i B) \sqrt{a+i a \tan (c+d x)}}{30 a^3 d}+\frac{(A-i B) \operatorname{Subst}\left (\int \frac{1}{2 a-x^2} \, dx,x,\sqrt{a+i a \tan (c+d x)}\right )}{4 a^2 d}\\ &=\frac{(A-i B) \tanh ^{-1}\left (\frac{\sqrt{a+i a \tan (c+d x)}}{\sqrt{2} \sqrt{a}}\right )}{4 \sqrt{2} a^{5/2} d}+\frac{(i A-B) \tan ^3(c+d x)}{5 d (a+i a \tan (c+d x))^{5/2}}+\frac{(7 A+17 i B) \tan ^2(c+d x)}{30 a d (a+i a \tan (c+d x))^{3/2}}+\frac{41 A+151 i B}{60 a^2 d \sqrt{a+i a \tan (c+d x)}}+\frac{(13 A+83 i B) \sqrt{a+i a \tan (c+d x)}}{30 a^3 d}\\ \end{align*}
Mathematica [A] time = 4.2232, size = 193, normalized size = 0.91 \[ -\frac{15 (A-i B) e^{5 i (c+d x)} \sqrt{1+e^{2 i (c+d x)}} \sinh ^{-1}\left (e^{i (c+d x)}\right )+A \left (-16 e^{2 i (c+d x)}+64 e^{4 i (c+d x)}+83 e^{6 i (c+d x)}+3\right )+i B \left (-26 e^{2 i (c+d x)}+194 e^{4 i (c+d x)}+463 e^{6 i (c+d x)}+3\right )}{15 a^2 d \left (1+e^{2 i (c+d x)}\right )^3 (\tan (c+d x)-i)^2 \sqrt{a+i a \tan (c+d x)}} \]
Antiderivative was successfully verified.
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Maple [A] time = 0.03, size = 142, normalized size = 0.7 \begin{align*} -2\,{\frac{1}{{a}^{3}d} \left ( -iB\sqrt{a+ia\tan \left ( dx+c \right ) }-1/8\,{\frac{a \left ( 7\,A+17\,iB \right ) }{\sqrt{a+ia\tan \left ( dx+c \right ) }}}+1/12\,{\frac{{a}^{2} \left ( 5\,A+7\,iB \right ) }{ \left ( a+ia\tan \left ( dx+c \right ) \right ) ^{3/2}}}-1/10\,{\frac{{a}^{3} \left ( A+iB \right ) }{ \left ( a+ia\tan \left ( dx+c \right ) \right ) ^{5/2}}}-1/16\,\sqrt{a} \left ( A-iB \right ) \sqrt{2}{\it Artanh} \left ( 1/2\,{\frac{\sqrt{a+ia\tan \left ( dx+c \right ) }\sqrt{2}}{\sqrt{a}}} \right ) \right ) } \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F(-2)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: ValueError} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [B] time = 2.05867, size = 1100, normalized size = 5.21 \begin{align*} \frac{{\left (15 \, \sqrt{\frac{1}{2}} a^{3} d \sqrt{\frac{A^{2} - 2 i \, A B - B^{2}}{a^{5} d^{2}}} e^{\left (6 i \, d x + 6 i \, c\right )} \log \left (\frac{{\left (2 i \, \sqrt{\frac{1}{2}} a^{3} d \sqrt{\frac{A^{2} - 2 i \, A B - B^{2}}{a^{5} d^{2}}} e^{\left (2 i \, d x + 2 i \, c\right )} + \sqrt{2}{\left ({\left (i \, A + B\right )} e^{\left (2 i \, d x + 2 i \, c\right )} + i \, A + B\right )} \sqrt{\frac{a}{e^{\left (2 i \, d x + 2 i \, c\right )} + 1}} e^{\left (i \, d x + i \, c\right )}\right )} e^{\left (-i \, d x - i \, c\right )}}{i \, A + B}\right ) - 15 \, \sqrt{\frac{1}{2}} a^{3} d \sqrt{\frac{A^{2} - 2 i \, A B - B^{2}}{a^{5} d^{2}}} e^{\left (6 i \, d x + 6 i \, c\right )} \log \left (\frac{{\left (-2 i \, \sqrt{\frac{1}{2}} a^{3} d \sqrt{\frac{A^{2} - 2 i \, A B - B^{2}}{a^{5} d^{2}}} e^{\left (2 i \, d x + 2 i \, c\right )} + \sqrt{2}{\left ({\left (i \, A + B\right )} e^{\left (2 i \, d x + 2 i \, c\right )} + i \, A + B\right )} \sqrt{\frac{a}{e^{\left (2 i \, d x + 2 i \, c\right )} + 1}} e^{\left (i \, d x + i \, c\right )}\right )} e^{\left (-i \, d x - i \, c\right )}}{i \, A + B}\right ) + \sqrt{2}{\left ({\left (83 \, A + 463 i \, B\right )} e^{\left (6 i \, d x + 6 i \, c\right )} + 2 \,{\left (32 \, A + 97 i \, B\right )} e^{\left (4 i \, d x + 4 i \, c\right )} - 2 \,{\left (8 \, A + 13 i \, B\right )} e^{\left (2 i \, d x + 2 i \, c\right )} + 3 \, A + 3 i \, B\right )} \sqrt{\frac{a}{e^{\left (2 i \, d x + 2 i \, c\right )} + 1}} e^{\left (i \, d x + i \, c\right )}\right )} e^{\left (-6 i \, d x - 6 i \, c\right )}}{120 \, a^{3} d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-2)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: AttributeError} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{{\left (B \tan \left (d x + c\right ) + A\right )} \tan \left (d x + c\right )^{3}}{{\left (i \, a \tan \left (d x + c\right ) + a\right )}^{\frac{5}{2}}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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